Help with projectile motion!?

This is a vector and g problem. Let's use sin 37 =.60, cos 37 = .80, and g= 10m/sec^. The vertical component of it's flight will be (.60)(30m/sec) = 18m/sec. How long will it take gravity to slow that to 0 and then re-accelerate to 18m/sec? Use: v=gt....18=(10)(t)...18/10=t....1.8 sec = t. The ball will rise and then fall for a total of 3.6 sec. Assuming zero friction loss and a horizontal velocity of cos 37 times 30m/sec, Use v = (.8)(30) = 24m/sec. you get L = (24)(3.6) = 86.4 meters. It's speed and horizontal v will remain constant at 30 m/sec. The ball will rise L = (1/2)(gt^= (1/2)(10)(1.8)(1.8)= 16.2m.It will fall back down L = (1/2) gt^ .... L= (1/2)(10)(.2)(.2) ...L = .2m. It will be 16.2 -.2m =16m